155、最小栈
设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。
push(x) —— 将元素 x 推入栈中。
pop() —— 删除栈顶的元素。
top() —— 获取栈顶元素。
getMin() —— 检索栈中的最小元素。
示例:
输入:
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
输出:
[null,null,null,null,-3,null,0,-2]
解释:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> 返回 -3.
minStack.pop();
minStack.top(); --> 返回 0.
minStack.getMin(); --> 返回 -2.
提示:
- pop、top 和 getMin 操作总是在 非空栈 上调用。
题解
1、用ArrayList存储、线性查找最小元素
class MinStack {
ArrayList<Integer> stack;
/** initialize your data structure here. */
public MinStack() {
stack = new ArrayList<>(100);
}
public void push(int x) {
stack.add(x);
}
public void pop() {
stack.remove(stack.size()-1);
}
public int top() {
return stack.get(stack.size() - 1);
}
public int getMin() {
int t = stack.get(0);
for(int x : stack) {
if (t > x) {
t = x;
}
}
return t;
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
2、添加一个存储最小的元素的ArrayList
class MinStack {
ArrayList<Integer> stack;
ArrayList<Integer> minStack;
int min = Integer.MAX_VALUE;
/** initialize your data structure here. */
public MinStack() {
stack = new ArrayList<>(100);
minStack = new ArrayList<>(100);
minStack.add(min);
}
public void push(int x) {
if (min > x){
min = x;
}
minStack.add(min);
stack.add(x);
}
public void pop() {
stack.remove(stack.size() - 1);
minStack.remove(minStack.size() - 1);
min = minStack.get(minStack.size() - 1);
}
public int top() {
return stack.get(stack.size() - 1);
}
public int getMin() {
return min;
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
转载请注明来源,欢迎对文章中的引用来源进行考证,欢迎指出任何有错误或不够清晰的表达。可以在下面评论区评论,也可以邮件至 1056615746@qq.com